Algorithms for the arithmetic-geometric mean¶
With complex variables, it is convenient to work with the univariate function \(M(z) = \operatorname{agm}(1,z)\). The general case is given by \(\operatorname{agm}(a,b) = a M(1,b/a)\).
Functional equation¶
If the real part of z initially is not completely nonnegative, we apply the functional equation \(M(z) = (z+1) M(u) / 2\) where \(u = \sqrt{z} / (z+1)\).
Note that u has nonnegative real part, absent rounding error. It is not a problem for correctness if rounding makes the interval contain negative points, as this just inflates the final result.
For the derivative, the functional equation becomes \(M'(z) = [M(u) - (z-1) M'(u) / ((1+z) \sqrt{z})] / 2\).
AGM iteration¶
Once z is in the right half plane, we can apply the AGM iteration (\(2a_{n+1} = a_n + b_n, b_{n+1}^2 = a_n b_n\)) directly. The correct square root is given by \(\sqrt{a} \sqrt{b}\), which is computed as \(\sqrt{ab}, i \sqrt{-ab}, -i \sqrt{-ab}, \sqrt{a} \sqrt{b}\) respectively if both a and b have positive real part, nonnegative imaginary part, nonpositive imaginary part, or otherwise.
It is shown in [Dup2006], p. 87 that, for z with nonnegative real part, \(|M(z) - a_n| \le |a_n - b_n|\).
A small improvement would be to switch to a series expansion for the last one or two steps.
First derivative¶
Assuming that z is exact and that \(|\arg(z)| \le 3 \pi / 4\), we compute \((M(z), M'(z))\) simultaneously using a finite difference.
The basic inequality we need is \(|M(z)| \le \max(1, |z|)\), which is an immediate consequence of the AGM iteration.
By Cauchy’s integral formula, \(|M^{(k)}(z) / k!| \le C D^k\) where \(C = \max(1, |z| + r)\) and \(D = 1/r\), for any \(0 < r < |z|\) (we choose r to be of the order \(|z| / 4\)). Taylor expansion now gives
assuming that h is chosen so that it satisfies \(h D < 1\).
The forward finite difference requires two function evaluations at doubled precision. It would be more efficient to use a central difference (this could be implemented in the future).
When z is not exact, we evaluate at the midpoint as above and bound the propagated error using derivatives. Again by Cauchy’s integral formula, we have
assuming that the circle centered on z with radius \(|\varepsilon| + r\) does not cross the negative half axis. We choose r of order \(|z| / 2\) and verify that all assumptions hold.
Higher derivatives¶
The function \(W(z) = 1 / M(z)\) is D-finite. The coefficients of \(W(z+x) = \sum_{k=0}^{\infty} c_k x^k\) satisfy
in general, and
when \(z = 1\).